Solidification and cast structures
Take the densities of pure aluminum at its melting point (660 °C) as 2.375 g/cm³ for the liquid and 2.55 g/cm³ for the solid. Which is closest to the decrease in volume relative to the liquid volume (solidification shrinkage) when the liquid turns entirely into solid at the melting point?
- AAbout 2.3%
- BAbout 7.4%
- CAbout 6.9%
Show answer and explanation
Answer: C. About 6.9%
For a mass m, the volume is m/2.375 as a liquid and m/2.55 as a solid. The decrease relative to the liquid volume is 1 − 2.375/2.55 ≈ 0.069, about 6.9%. About 7.4% is the density difference divided by the liquid density, which corresponds to the decrease relative to the solid volume. About 2.3% converts the volume decrease into a linear contraction (1 − 0.931^(1/3)). Solidification shrinkage occurs during solidification, separately from the liquid contraction while the liquid cools and the solid contraction after it has solidified, so unless molten metal is fed from a riser it becomes a shrinkage cavity. In gray cast iron, by contrast, low-density graphite precipitates and expands during solidification, so the shrinkage is small and smaller risers can be used. Some substances, such as Si and Bi, even increase in volume on solidification.
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