Thermodynamics of materials
In an Ellingham diagram, the formation reactions of all oxides are drawn with ΔG° normalized per mol of O₂. What is the main advantage of doing so?
- AAll the ΔG° values become positive and lie above the temperature axis, so the scale is easier to read
- BThe vertical distance between 2 lines is directly equal to the ΔG° of the reaction in which one metal reduces the other's oxide
- CThe ΔS° that sets the slope becomes equal for all oxides, so the lines can be compared as parallel lines
Show answer and explanation
Answer: B. The vertical distance between 2 lines is directly equal to the ΔG° of the reaction in which one metal reduces the other's oxide
With normalization per mol of O₂, taking the difference between, for example, 4/3 Al + O₂ → 2/3 Al₂O₃ and 2Fe + O₂ → 2FeO cancels the O₂, and the ΔG° of 2FeO + 4/3 Al → 2Fe + 2/3 Al₂O₃ can be read directly as the vertical distance between the 2 lines. The metal of the lower line can reduce the oxide of the upper line at that temperature. The ΔG° of oxide formation is almost always negative, and the normalization does not change its sign. The slopes are set by the ΔS° of each reaction, so they do not become equal even when normalized per mol of O₂. In metal oxidation, 1 mol of gaseous O₂ is consumed in every case, which only makes the slopes similar.