Thermodynamics of materials
At 1000℃, take ΔG° for 4/3 Al + O₂ → 2/3 Al₂O₃ as −850 kJ/mol and ΔG° for 4/3 Cr + O₂ → 2/3 Cr₂O₃ as −530 kJ/mol (both per mol of O₂). Which combination of the ΔG° of 2/3 Cr₂O₃ + 4/3 Al → 2/3 Al₂O₃ + 4/3 Cr and the direction in which the reaction proceeds is correct? Assume all substances are pure.
- A−320 kJ/mol; it proceeds in the direction of aluminum reducing Cr₂O₃
- B+320 kJ/mol; it proceeds in reverse, in the direction of chromium reducing Al₂O₃
- C−1380 kJ/mol; it proceeds in the direction of aluminum reducing Cr₂O₃
Show answer and explanation
Answer: A. −320 kJ/mol; it proceeds in the direction of aluminum reducing Cr₂O₃
The required reaction is the Al₂O₃ formation equation minus the Cr₂O₃ formation equation, and the O₂ cancels. ΔG° = (−850) − (−530) = −320 kJ/mol is negative, so the reaction proceeds in the direction of aluminum reducing Cr₂O₃ to give metallic chromium. This corresponds to the Al₂O₃ line lying below the Cr₂O₃ line in the Ellingham diagram, and it is the principle of making metallic chromium by the aluminothermic process. +320 kJ/mol reverses the order of subtraction and gets the sign wrong; because Al₂O₃ is the more stable oxide, chromium does not reduce Al₂O₃. −1380 kJ/mol is the value obtained by adding the 2 ΔG° values.