Surface treatment and tribology
In the adhesion theory (the view of Bowden and Tabor), the friction force is set by the force needed to shear the adhesive junctions at the real contact spots, and the friction coefficient is μ = s/H (s is the shear strength of the junctions and H is the indentation hardness of the softer material). For s = 0.30 GPa and H = 1.8 GPa, which is closest to μ?
- AAbout 0.17
- BAbout 6.0
- CAbout 0.50
Show answer and explanation
Answer: A. About 0.17
μ = s/H = 0.30/1.8 ≈ 0.17. The friction force is the product F = sAr of the real area of contact Ar = W/H and the junction shear strength s, so F/W = s/H, giving a friction coefficient that depends neither on the load nor on the apparent area. About 6.0 is the value with numerator and denominator swapped, and about 0.50 is the value obtained by dividing by the yield stress estimate H/3 = 0.60 GPa instead of the hardness. Between real metals, the growth of junctions under combined load and shear (junction growth) and ploughing by hard asperities add to this, so μ is often larger than 0.17. The formula also shows that lowering the shear strength s with a lubricant film or an oxide film lowers μ.