Materials selection and design
Beams of square cross section designed for the same length and bending stiffness are made of steel (E = 210 GPa, ρ = 7.8 g/cm³) and an aluminum alloy (E = 70 GPa, ρ = 2.7 g/cm³). If the size of the cross section can be varied freely, about how many times the mass of the steel beam is the mass of the aluminum alloy beam?
- AAbout 0.60 times
- BAbout 0.35 times
- CAbout 1.04 times
Show answer and explanation
Answer: A. About 0.60 times
The mass of a beam with specified stiffness is proportional to ρ/√E. For the aluminum alloy it is 2.7/√70 = 2.7/8.37 ≈ 0.323, and for steel 7.8/√210 = 7.8/14.5 ≈ 0.538, so the ratio is 0.323/0.538 ≈ 0.60, about 0.60 times. The aluminum alloy beam needs a thicker section because its Young's modulus is one third, but thanks to its low density it is about 40% lighter overall. About 0.35 times looks only at the density ratio (2.7/7.8), ignoring that the section must be thicker to match stiffness. About 1.04 times is the value when mass is proportional to ρ/E, as for a tie in tension; for a tie, aluminum alloy and steel weigh almost the same.