High-temperature materials and creep

What is the main purpose of adding a few percent of heavy elements such as rhenium (Re) to single-crystal nickel-based superalloys?

  1. ATo dissolve in the γ matrix and slow diffusion, giving solid-solution strengthening and slower γ' coarsening, and so raise creep strength at high temperature
  2. BTo form on the surface a dense film of rhenium oxide that hardly volatilizes, raising the oxidation resistance at high temperatures in place of the Al₂O₃ film
  3. CTo lower the alloy's density, reducing the centrifugal stress on the fast-rotating blade and so extending the creep rupture life at the same temperature
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Answer: A. To dissolve in the γ matrix and slow diffusion, giving solid-solution strengthening and slower γ' coarsening, and so raise creep strength at high temperature

Re is an element that diffuses very slowly in the alloy and partitions mainly to the γ matrix, where it dissolves. Besides solid-solution strengthening of γ, it slows the coarsening of γ' and rafting, in which γ' joins into plates under stress at high temperature, greatly raising creep strength. Generations of single-crystal alloys are sometimes distinguished by their Re content, such as second-generation alloys with about 3% Re and third-generation alloys with about 6%. However, too much Re makes brittle TCP phases such as the σ phase likely to precipitate. Re is a heavy element, so it raises rather than lowers the density, and its oxide is volatile and does not form a protective film. Oxidation resistance is provided mainly by the Al₂O₃ film formed by Al.

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More High-temperature materials and creep questions

  1. When an alloy was oxidized in air at high temperature, it followed the parabolic law x² = k_p t, in which diffusion through the dense oxide scale controls the rate, and the scale was 2.0 µm thick after 100 h. Which is closest to the scale thickness after 900 h of oxidation at the same temperature?
  2. The Pilling–Bedworth ratio of a metal's oxide scale (PBR, the ratio of the volume of oxide to the volume of metal used to form it) is calculated as PBR = (M_ox ρ_M)/(n M_M ρ_ox) (M is the molar mass, ρ is the density, and n is the number of metal atoms in one formula unit of the oxide). For magnesium (24.31 g/mol, 1.74 g/cm³) and MgO (40.30 g/mol, 3.58 g/cm³, n = 1), which combination of PBR and scale behavior is correct?
  3. Which statement about the protective scales on heat-resistant alloys used in air at high temperatures above 1000 °C is correct?
  4. Which statement about the structure of a thermal barrier coating (TBC) applied to gas turbine blades is correct?
  5. A heat flux of 1.0 MW/m² passes uniformly through the thickness of the top coat of a thermal barrier coating (thickness 250 µm, thermal conductivity 1.2 W/(m·K)). Treating it as steady one-dimensional heat conduction, which is closest to the temperature difference between the two faces of the top coat?