High-temperature materials and creep

Why are directionally solidified columnar-grained or single-crystal nickel-based superalloys used for jet engine turbine blades?

  1. ABecause a single crystal contains no dislocations at all, so creep deformation cannot occur
  2. BBecause a single crystal allows more carbon and boron, which are used to strengthen grain boundaries, to be added, so the alloy can be strengthened by their carbides and borides
  3. CBecause removing grain boundaries perpendicular to the stress eliminates the sites where creep damage starts, and a single crystal can do without grain-boundary-strengthening elements, so it can be solution treated at high temperature to make γ' uniform and fine
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Answer: C. Because removing grain boundaries perpendicular to the stress eliminates the sites where creep damage starts, and a single crystal can do without grain-boundary-strengthening elements, so it can be solution treated at high temperature to make γ' uniform and fine

Turbine blades are pulled along their length by centrifugal force, and grain boundaries perpendicular to the stress become the starting points of creep voids and cracks. Directional solidification produces columnar grains aligned with the stress, removing the perpendicular boundaries. In single-crystal blades, grown so that only one crystal is selected, there are no grain boundaries at all. When C, B, Zr and other grain-boundary strengtheners are no longer needed, the temperature at which the alloy begins to melt rises, so solution treatment can be done at high temperature to dissolve γ' fully and then reprecipitate it uniformly and finely. The statement about adding more strengtheners reverses this relationship. Single crystals still contain dislocations, and creep proceeds by their motion within the crystal.

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More High-temperature materials and creep questions

  1. What is the main purpose of adding a few percent of heavy elements such as rhenium (Re) to single-crystal nickel-based superalloys?
  2. When an alloy was oxidized in air at high temperature, it followed the parabolic law x² = k_p t, in which diffusion through the dense oxide scale controls the rate, and the scale was 2.0 µm thick after 100 h. Which is closest to the scale thickness after 900 h of oxidation at the same temperature?
  3. The Pilling–Bedworth ratio of a metal's oxide scale (PBR, the ratio of the volume of oxide to the volume of metal used to form it) is calculated as PBR = (M_ox ρ_M)/(n M_M ρ_ox) (M is the molar mass, ρ is the density, and n is the number of metal atoms in one formula unit of the oxide). For magnesium (24.31 g/mol, 1.74 g/cm³) and MgO (40.30 g/mol, 3.58 g/cm³, n = 1), which combination of PBR and scale behavior is correct?
  4. Which statement about the protective scales on heat-resistant alloys used in air at high temperatures above 1000 °C is correct?
  5. Which statement about the structure of a thermal barrier coating (TBC) applied to gas turbine blades is correct?