Mechanical properties and fracture

Take about 0.4 times the melting point (in absolute temperature) as the rough temperature above which creep can no longer be ignored. For aluminum (melting point 660 °C), which value is closest to this temperature?

  1. AAbout 100 °C
  2. BAbout 264 °C
  3. CAbout 373 °C
Show answer and explanation

Answer: A. About 100 °C

This rule of thumb works in absolute temperature, so with Tm = 660 + 273 = 933 K, 0.4Tm ≈ 373 K, about 100 °C. About 264 °C is the mistake of computing 0.4 × 660 in °C, and about 373 °C mistakes 373 K for °C. This ratio (the homologous temperature) varies between materials, roughly 0.3–0.5, but for aluminum alloys creep and loss of strength must be considered from about 100 °C upward, and low-melting solders creep even at room temperature. Creep proceeds through three stages, primary, secondary (steady-state) and tertiary, before rupture, and the steady-state creep rate is the key quantity in design.

Report an error

Practice this topic Back to topic

Related calculators

More Mechanical properties and fracture questions

  1. Which material shows a distinct ductile-to-brittle transition at low temperatures?
  2. Which statement about the Young's modulus of steel is correct?
  3. A round bar 10 mm in diameter carries a tensile load of 10 kN. Which value is closest to the engineering stress?
  4. A steel rod 2.0 m long with a Young's modulus of 200 GPa is loaded in tension to 100 MPa within its elastic range. Which value is closest to the elongation of the rod?
  5. For materials such as aluminum alloys that show no distinct yield point, which correctly describes how the 0.2% offset yield strength is determined?