Mechanical properties and fracture
A steel rod 2.0 m long with a Young's modulus of 200 GPa is loaded in tension to 100 MPa within its elastic range. Which value is closest to the elongation of the rod?
- AAbout 0.10 mm
- BAbout 1.0 mm
- CAbout 10 mm
Show answer and explanation
Answer: B. About 1.0 mm
From Hooke's law, the strain is ε = σ/E = 100×10⁶ / (200×10⁹) = 5.0×10⁻⁴. The elongation is ΔL = εL = 5.0×10⁻⁴ × 2000 mm = 1.0 mm. About 0.10 mm and about 10 mm are off by one order of magnitude from a slip in the GPa–MPa conversion (1 GPa = 1000 MPa) or the m–mm conversion. Even in a steel with a yield stress of several hundred MPa, the elastic strain stays at only about 0.1–0.2%. At the same stress, an aluminum alloy with about one third the modulus (about 70 GPa) stretches about three times as much, a difference that matters in stiffness-critical design.
Continue: 9 more Mechanical properties and fracture questions