Nanomaterials
Suppose the melting point of spherical metal nanoparticles can be approximated in terms of the diameter d as Tm(d) = Tm∞(1 − β/d). With the bulk melting point of gold Tm∞ = 1337 K and β taken as a hypothetical model value of 1.0 nm, which value is closest to the melting point of gold nanoparticles 5.0 nm in diameter?
- AAbout 802 K
- BAbout 1604 K
- CAbout 1070 K
Show answer and explanation
Answer: C. About 1070 K
β/d = 1.0/5.0 = 0.20, so Tm(d) = 1337 × (1 − 0.20) = 1337 × 0.80 ≈ 1070 K (about 796 °C), about 270 K below the melting point of bulk gold. About 802 K puts the radius, 2.5 nm, in place of d, giving 1 − 0.40, and about 1604 K reverses the sign to (1 + β/d), which would mean the melting point rises in nanoparticles. This expression is an approximation derived from the surface energy contribution being inversely proportional to size, and β = 1.0 nm is a value assumed for this problem. The actual β varies with the metal, the particle shape and the surrounding medium, and the approximation becomes rough as the size approaches about 2 nm, so it can deviate from measured melting points.