Solidification and cast structures
Suppose Chvorinov's rule t = B(V/A)² holds (t is the solidification time, V the volume, A the surface area and B a constant). Under the same mold conditions, a cube-shaped casting of a certain volume solidified in 10 minutes. Which is closest to the solidification time of a spherical casting of the same volume?
- AAbout 15 minutes
- BAbout 12 minutes
- C10 minutes
Show answer and explanation
Answer: A. About 15 minutes
Even at the same volume, a sphere has the smallest surface area of any shape, so its V/A (modulus) is larger. For a cube of edge a, V/A = a/6 ≈ 0.167a. The radius of a sphere of the same volume is r = (3a³/4π)^(1/3) ≈ 0.620a, so V/A = r/3 ≈ 0.207a, about 1.24 times that of the cube. The solidification time is the square of this, about 1.54 times, giving 10 × 1.54 ≈ 15 minutes. About 12 minutes assumes the time is proportional to V/A, and 10 minutes is the mistake of thinking that the same volume means the same solidification time. A riser must stay liquid longer than the casting it feeds, so it is given a shape that makes V/A large for the amount of metal, such as a sphere or a cylinder with height about equal to its diameter.
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