Fracture mechanics and fatigue

A cyclic stress with a mean stress σm = 200 MPa is applied to a steel with a fully reversed fatigue limit σw = 300 MPa and a tensile strength σB = 800 MPa. Using the modified Goodman relation σa = σw(1 − σm/σB), which value is closest to the stress amplitude corresponding to the fatigue limit?

  1. AAbout 281 MPa
  2. BAbout 225 MPa
  3. CAbout 100 MPa
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Answer: B. About 225 MPa

σm/σB = 200/800 = 0.25, so σa = 300×(1 − 0.25) = 225 MPa. A tensile mean stress acts to open cracks, so the allowable stress amplitude is smaller than the fully reversed value (σm = 0). The modified Goodman diagram is a conservative guide that joins σw on the vertical axis and σB on the horizontal axis with a straight line. About 281 MPa is the value from the parabolic Gerber relation, which squares the mean stress ratio, 300×(1 − 0.25²), and is a less conservative estimate than Goodman. About 100 MPa divides by σw instead of σB. A compressive mean stress often works in favor of fatigue resistance, but designs usually do not take credit for that effect.

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More Fracture mechanics and fatigue questions

  1. Which surface treatment can be expected to improve the fatigue strength of a steel part?
  2. A steel part fails by fatigue after 1.0×10⁵ cycles at stress amplitude σ₁ and after 1.0×10⁶ cycles at σ₂. After it is used for 4.0×10⁴ cycles at σ₁, it continues to be used at σ₂. Which value is closest to the remaining life estimated with Miner's rule (failure when Σn/N = 1)?
  3. Which statement about low-cycle fatigue (roughly 10⁴ cycles or fewer to failure) is correct?
  4. Which statement correctly describes the curve of fatigue crack growth rate da/dN plotted against the stress intensity factor range ΔK on log-log axes?
  5. Fatigue crack growth in a steel plate is described by the Paris law da/dN = C(ΔK)ᵐ (C = 1.0×10⁻¹², with da/dN in m/cycle, ΔK in MPa·√m, and m = 4), and ΔK = Δσ√(πa) (geometry factor 1). Under cycling with a stress range Δσ = 200 MPa, which value is closest to the number of cycles for the crack to grow from 1.0 mm to 5.0 mm? Assume that ΔK over this range (about 11–25 MPa·√m) is well above the threshold and within the range where the Paris law holds.