What is Scherrer equation?
The equation D = Kλ/(β cosθ) for estimating crystallite size from the broadening of XRD peaks, where β is the full width at half maximum in radians and K is about 0.9.
Japanese name: シェラーの式
Scherrer equation appears in 2 practice questions across 2 topics, including Materials characterization (SEM, TEM, XRD, XPS), Nanomaterials.
Field: Materials characterization (SEM, TEM, XRD, XPS)
Why peaks broaden
In a large crystal, scattering from many lattice planes cancels as soon as the angle deviates slightly from the Bragg angle, so the peak is sharp. When the crystallite is small and few planes diffract together, this cancellation is incomplete, and intensity remains over a wider range of angles around the Bragg angle. The Scherrer equation D = Kλ/(β cosθ) expresses the relation between this broadening and crystallite size; the broadening is inversely proportional to the size. For example, with Cu Kα radiation, a peak at 2θ = 30° with a full width at half maximum of 0.25° gives D of about 33 nm with K = 0.9.
Cautions when using the equation
β is an angle in radians, taken directly as the width measured on the 2θ scale, while θ is half of the peak position 2θ. The measured peak width also contains the broadening of the instrument itself, so the instrumental width is determined with a standard such as LaB₆ and subtracted (for Gaussian peaks, as the square root of the difference of squares). K depends on the crystallite shape and on whether β is the full width at half maximum or the integral breadth, and values around 0.9 are commonly used. As crystallites grow, the broadening is buried in the instrumental width, so the practical upper limit is roughly 100–200 nm.
FAQ
Why is the Scherrer constant K about 0.9?
Because the theoretical value for nearly spherical or cubic crystallites, with β taken as the full width at half maximum, is around 0.9. It changes somewhat with shape and the definition of width, so use the same K and the same width definition when comparing samples.
Should the peak width be entered in degrees or radians?
In radians. Multiply a width measured in degrees by π/180 to convert it. Entering it in degrees makes the crystallite size come out about 1/57 of the correct value.
Why is the size from the Scherrer equation smaller than the particle size seen by SEM?
Because each particle may consist of several crystallites, or non-uniform strain may be broadening the peaks. Twins and stacking faults also shrink the regions that diffract coherently, and so reduce the value.