What is Specific surface area?

The surface area per unit mass of a powder or porous body, in m²/g. For spherical particles S = 6/(ρd), increasing in inverse proportion to particle size.

Japanese name: 比表面積

Specific surface area appears in 6 practice questions across 3 topics, including Nanomaterials, Thin films, surfaces and nanomaterials, Ceramics and glasses.

Field: Nanomaterials

Try it: questions about Specific surface area

When the diameter of spherical particles is reduced from 1 µm to 10 nm, by what factor does the surface area per unit volume (specific surface area) increase?

  1. A10 times
  2. B100 times
  3. C10,000 times
Show answer and explanation

Answer: B. 100 times

A sphere has a surface area of 4πr² and a volume of (4/3)πr³, so the surface area per unit volume is 3/r, inversely proportional to the radius (diameter). When the diameter falls to 1/100, from 1 µm = 1000 nm to 10 nm, the specific surface area increases 100 times. Ten times takes the square root of the ratio, and 10,000 times confuses this with the ratio of the surface areas of single particles (the square of the diameter ratio). In particles about 10 nm in diameter, roughly a tenth of all atoms are at the surface, and the properties of the surface atoms strongly influence those of the particle as a whole. Nanoparticles are used as catalysts because of their large specific surface area.

Spherical TiO₂ nanoparticles 20 nm in diameter (density 4.0 g/cm³) are all the same size and fully dispersed. Which value is closest to the surface area per gram of powder (the specific surface area)?

  1. AAbout 37.5 m²/g
  2. BAbout 75 m²/g
  3. CAbout 150 m²/g
Show answer and explanation

Answer: B. About 75 m²/g

Dividing the surface area of one sphere, πd², by its mass, ρπd³/6, gives a specific surface area per mass of S = 6/(ρd). Substituting ρ = 4.0 g/cm³ = 4.0×10⁶ g/m³ and d = 20×10⁻⁹ m gives S = 6/(4.0×10⁶ × 20×10⁻⁹) = 6/0.080 = 75 m²/g. About 150 m²/g puts the radius, 10 nm, in place of d, and about 37.5 m²/g puts the diameter, 20 nm, in place of r in the radius form S = 3/(ρr). The specific surface area is inversely proportional to particle size, so halving the size doubles it. In real powders the particles touch and agglomerate, so measured values are usually smaller than this calculated value.

Specific surface area in the explanations

Questions that mention Specific surface area (6)

  1. When the diameter of spherical particles is reduced from 1 µm to 10 nm, by what factor does the surface area per unit volume (specific surface area) increase?
  2. Spherical TiO₂ nanoparticles 20 nm in diameter (density 4.0 g/cm³) are all the same size and fully dispersed. Which value is closest to the surface area per gram of powder (the specific surface area)?
  3. Which correctly describes the principle of the BET method for measuring the specific surface area of a powder?
  4. For an alumina nanopowder, the primary particle diameter observed by TEM was about 30 nm, and the particle size obtained from the BET specific surface area assuming spheres was also about 30 nm. However, the mean particle size measured by dynamic light scattering after dispersing it in water was about 400 nm. Which interpretation of these results is most appropriate?
  5. Which statement about sintering of ceramic powders is correct?
  6. Which is an appropriate way to keep oxide nanoparticles dispersed in water from agglomerating and settling?

Related terms

BET method XRD (X-ray diffraction) Scherrer equation Sintering Zeta potential Bottom-up synthesis Carbon nanotube Graphene Melting point depression of nanoparticles Quantum dot

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