What is Pearlite?

The microstructure formed by the eutectoid reaction in steel, with alternating lamellae of ferrite and cementite. The faster the cooling, the finer the lamellar spacing and the harder the pearlite.

Japanese name: パーライト

Pearlite appears in 5 practice questions across 2 topics, including Phase diagrams and the lever rule, Heat treatment and metallic materials.

Field: Phase diagrams and the lever rule

How pearlite forms

When austenite of eutectoid composition transforms slightly below the A1 point, pearlite forms mainly from the austenite grain boundaries. Ferrite and cementite grow simultaneously side by side, and just ahead of the growth front, carbon diffuses from the ferrite side to the cementite side and is handed over. A region in which the lamellae share an orientation is called a colony, and many colonies with different orientations form within one austenite grain. The name comes from the pearl-like luster of a polished and etched surface.

Lamellar spacing sets the strength

The lamellar spacing of pearlite becomes finer the lower the transformation temperature (the greater the undercooling), roughly in inverse proportion to the undercooling, because carbon has to diffuse a shorter distance and more nuclei form. The finer the spacing, the shorter the distance dislocations can travel in the ferrite, so yield strength and hardness rise; a relation in which they are proportional to the inverse square root of the spacing is widely used. Furnace cooling gives coarse pearlite and air cooling (normalizing) gives fine pearlite, so strength changes even at the same carbon content.

Difference from bainite and spheroidized structures

Transformation at temperatures below the pearlite range but above the range where martensite forms produces bainite, in which cementite is dispersed not as lamellae but as fine particles or rods in or between the ferrite. When pearlite is held for a long time just below the A1 point, the cementite becomes rounded to lower its surface energy, giving a spheroidized structure. Spheroidized steel is the softest possible at a given carbon content and is easy to machine and cold-work, so this treatment is used on bearing and tool steels before machining.

Use in piano wire and rails

High-carbon steel wire rod is transformed isothermally to fine pearlite in a lead bath or similar at about 500–550 °C (patenting) and is then heavily cold-drawn. Drawing makes the lamellar spacing even finer, and piano wire, bridge suspension cables and tire reinforcing cords reach tensile strengths well above 2 GPa. Railway rails also use wear-resistant pearlitic steel, and some have heads heat-treated to fine pearlite. Pearlite is a long-established microstructure, but it remains one of the mainstays of high-strength materials today.

Try it: questions about Pearlite

Which statement about the eutectoid point of the Fe-Fe₃C phase diagram is correct?

  1. AAt about 0.76 wt% C and 727 °C, γ → α + Fe₃C occurs and pearlite forms
  2. BAt about 4.3 wt% C and 1147 °C, L → γ + Fe₃C occurs and lamellar pearlite forms
  3. CAt about 0.022 wt% C and 912 °C, γ → α occurs and bainite forms
Show answer and explanation

Answer: A. At about 0.76 wt% C and 727 °C, γ → α + Fe₃C occurs and pearlite forms

The eutectoid point of the Fe-Fe₃C system is at about 0.76 wt% C and 727 °C, where austenite (γ) transforms into pearlite, a lamellar structure of ferrite (α) and cementite (Fe₃C). The reaction at about 4.3 wt% C and 1147 °C is the eutectic reaction involving the liquid, and the structure it produces is ledeburite, not pearlite. 0.022 wt% C is the maximum solubility of carbon in α at 727 °C, and 912 °C is the γ → α transformation temperature of pure iron. Bainite does not appear on the equilibrium phase diagram; it is a nonequilibrium structure that forms from undercooled austenite in an intermediate temperature range. Steels with less carbon than the eutectoid composition are called hypoeutectoid, and those with more are called hypereutectoid.

A 0.40 wt% C hypoeutectoid steel is cooled under equilibrium to just below 727 °C. Which value is closest to the mass fraction of proeutectoid ferrite? Take the eutectoid composition as 0.76 wt% C, the carbon content of ferrite at 727 °C as 0.022 wt% C, and cementite as 6.70 wt% C.

  1. AAbout 0.51
  2. BAbout 0.94
  3. CAbout 0.49
Show answer and explanation

Answer: C. About 0.49

Proeutectoid ferrite is the ferrite already formed in the α + γ region just above 727 °C, and all the remaining γ becomes pearlite. From the lever rule, W_proeutectoid α = (0.76 − 0.40)/(0.76 − 0.022) = 0.36/0.738 ≈ 0.49. About 0.51 is the fraction of the remaining pearlite, the mistake of taking the opposite distance. About 0.94 is the fraction of all ferrite treating the steel as the two phases α + Fe₃C, (6.70 − 0.40)/(6.70 − 0.022), which includes the ferrite inside the pearlite as well. The area ratio of proeutectoid ferrite to pearlite in a micrograph is a clue for estimating the carbon content of a hypoeutectoid steel.

FAQ

What is the difference between pearlite and martensite?

Pearlite is a near-equilibrium structure in which carbon has diffused and the steel has separated into ferrite and cementite. Martensite is a non-equilibrium structure formed when quenching prevents diffusion and the steel transforms by shear while retaining carbon in supersaturation; it is far harder and more brittle.

Why does pearlite look dark under the microscope?

Etching with nital or a similar reagent turns the lamella boundaries into grooves that scatter light. At low magnification the fine lamellae cannot be resolved, so the whole area looks dark. The regions that look white are ferrite or proeutectoid cementite.

How can the lamellar spacing of pearlite be made finer?

Lower the transformation temperature (cool faster). Normalizing with air cooling and patenting with isothermal transformation around 500 °C give fine pearlite. If cooling is too fast, however, bainite or martensite forms.

Pearlite in the explanations

Questions that mention Pearlite (5)

  1. Which statement about the eutectoid point of the Fe-Fe₃C phase diagram is correct?
  2. A 0.40 wt% C hypoeutectoid steel is cooled under equilibrium to just below 727 °C. Which value is closest to the mass fraction of proeutectoid ferrite? Take the eutectoid composition as 0.76 wt% C, the carbon content of ferrite at 727 °C as 0.022 wt% C, and cementite as 6.70 wt% C.
  3. When a 1.2 wt% C hypereutectoid steel is slowly cooled from the austenite region, what microstructure is obtained at room temperature?
  4. Which statement about the martensitic transformation in steel is correct?
  5. Adding alloying elements such as Mn, Cr and Mo to steel improves its hardenability. Which is the correct reason?

Related terms

Martensite Eutectic reaction Lever rule Eutectoid reaction Hardenability Gibbs phase rule

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